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Elementary right-triangle solving

Mathematics — first biennium · Lesson

Biennium · Scientific profile

Elementary right-triangle solving

Solving a triangle means finding missing measures from sufficient data. In a right triangle, one length and a trigonometric ratio can determine the other sides.

Key idea
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Similar example
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Prerequisites: Trigonometric ratios and Pythagoras

Goal: Find missing sides from a hypotenuse and trigonometric ratios and verify the result with Pythagoras.

What you need to know before the exercises

In this lesson: Find missing sides from a hypotenuse and trigonometric ratios and verify the result with Pythagoras.

New concept: Solving a triangle means determining its missing measures. In a right triangle, choose the trigonometric ratio containing the known side and the unknown side; the other acute angle is 90° minus the first.

How to proceed: Multiply the hypotenuse by each ratio. At the end verify that the two legs satisfy a²+b²=c².

You can already assume: Trigonometric ratios and Pythagoras.

Geometry view

Read the diagram

SVG
Geometry diagram for the exercise The triangle shows the sides obtained from the trigonometric ratios; Pythagoras provides an independent final check. A B C αadjacent=15opposite=36hypotenuse=39

The triangle shows the sides obtained from the trigonometric ratios; Pythagoras provides an independent final check.

Try it now

Use the trigonometric ratio as an equation between the unknown side and the hypotenuse, then check with Pythagoras.

Guided

Completed exercises: 0/5 · Correct on first attempt: 0

How to reason

Multiply the hypotenuse by each ratio. At the end verify that the two legs satisfy a²+b²=c².

Data / situation: A right triangle has hypotenuse 39, sin α=12/13 and cos α=5/13. Find the two legs relative to α.

Formula matematica
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